## Optional and Keyword Arguments

Arguments whose values are determined from their ordering in the parameter list are called positional variables. Python supports optional and keyword arguments as well. Optional arguments are assigned a default value in the parameter list of the function definition. If an optional argument is not present in the argument list passed by the caller, it takes on its default value; otherwise it is positional.

def func(x,y=0,w=3):
return x+y-w


We can call this function with

c=func(x)
c=func(x,yy)
c=func(x,yy,zz)


In this example the optional arguments are passed by position as usual. Optional arguments may also be passed by keyword, not position. Any optional/keyword arguments must follow any and all positional arguments in the list; except for that restriction their order does not matter and some may be omitted.

z=func(x,w=6,y=2)
val=func(x,w=9)


Default values are set only once, when the function is first encountered by the interpreter. Only immutable types should be used as default values.

## Variable Scope

The scope of a variable is the range over which it has a defined value. In Python, the scope is the code block in which the variable is first referenced. Therefore a calling program may have a variable x, a function may also have a variable x, and if x is not an argument to the function then it will be distinct in the two units.

Variables and function names defined at the outermost indentation level are global to the functions in the same file; that is, they are in scope in the entire file.

When working in the interpreter (including running codes through Spyder repeatedly in the same kernel), the interpreter stores all variables with global scope into a workspace. It may be desirable to reset these variables for new runs. In an iPython console you can type

%reset


to clear the workspace. In Jupyterlab you can also go to the URL bar and add ?reset at the end, viz

http://localhost:8888/lab?reset


Exercise

Experiment with the following code (leave in or comment out x=100)

def set_x(x):
print(x)
x=100
while x>0:
x+=1
if x>10000: break
if x<100: continue
x+=20
return x
x=1
z=set_x(x)
print(x)
print(z)


## Anonymous Functions

In Python we can use a lambda expression to evaluate a function without giving it an explicit definition. These are often called “anonymous functions” since they do not require naming. Lambdas must be expressible as a single expression; no statements are allowed. A tuple of the variable names follows the lambda keyword, then a colon, and finally the expression of the variables.

fsquared=lambda x:x**2
fsquared(4)
import math
fhypot=lambda x,y:math.sqrt(x**2+y**2)
fhypot(3,7)


One of the most common applications of lambda expressions is to the built-in functions map and filter, with reduce built in to Python 2.7 and available through functools in Python 3.

• map
• first argument is a function, second argument is a sequence
• applies the function to each element of the sequence and returns a new list (Python 2.7) or iterator (Python 3)
• L1=map(square,S) #Python 2.7
• L1=list(map(square,S)) #Python 3
• reduce
• first argument must be a function that takes two inputs and returns a single input of the same type
• total=reduce(sum,s) #Python 2.7
• import functools; total=functools.reduce(sum,s) #Python 3
• filter
• first argument is a function that returns True or False.
• applies the function to each element of the sequence and returns a new sequence (Python 2.7) or iterator (Python 3)
• L2=filter(func,s) #Python 2.7
• L2=list(filter(func,s)) #Python 3

Exercise

Print the results of the following code. Try to express map and filter with an equivalent list comprehension. For the equivalent to the reduction, try the sum built-in function. Note that not all reductions will have an equivalent built-in, but when available it may be faster than the corresponding reduce construct.


V=[-1,0,1,2,3,4,5]
L=list(map(lambda x:x**2, V))
R=functools.reduce(lambda x,y:x+y, V)
F=list(filter(lambda x:x>0, V))

Example solution

import functools

V=[-1,0,1,2,3,4,5]

L=list(map(lambda x:x**2, V))
R=functools.reduce(lambda x,y:x+y, V)
F=list(filter(lambda x:x>0, V))

print(L)
print(R)
print(F)

L2=[vel**2 for vel in V]
R2=sum(V)
F2=[vel for vel in V if vel>0]

print(L2)
print(R2)
print(F2)



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